PAPP Chapter 11: Thermodynamics
Multiple Choice (75)
Identify the letter of the choice that
best completes the statement or answers the question. Carefully mark your
scantron answer document.
1. A 2 mol ideal gas system is maintained at a
constant volume of 4 L. If the pressure is constant, how much work is done by
the system?
|
a. |
0 J |
c. |
8 J |
|
b. |
5 J |
d. |
30 J |
2. According to the first law of thermodynamics,
the difference between energy transferred to or from a system as heat and
energy transferred to or from a system by work is equivalent to which of the
following?
|
a. |
entropy change |
c. |
temperature change |
|
b. |
internal energy change |
d. |
specific heat |
3. According to the second law of
thermodynamics, the heat received by a heat engine operating in a complete
cycle from a high-temperature reservoir
|
a. |
must be completely converted to work. |
|
b. |
equals the entropy increase. |
|
c. |
can be completely converted to internal energy. |
|
d. |
cannot be completely converted to work. |
4. A chunk of ice with a mass of 1 kg at 0°C
melts and absorbs 3.35 ´ 108 J of heat in the process. Which best describes
what happened to this system?
|
a. |
Its entropy increased. |
c. |
Internal energy remained constant |
|
b. |
Its entropy decreased. |
d. |
Work was converted to energy. |
5. Sunlight strikes an ice cube at its melting
point and causes it to melt. What is this process?
|
a. |
adiabatic process |
c. |
isobaric process |
|
b. |
isothermal process |
d. |
isovolumetric process |
6. How is conservation of internal energy
expressed for an isothermal system?
|
a. |
Q = W = 0, so DU = 0 and Ui =
Uf |
|
b. |
Q = 0, so DU = –W |
|
c. |
DT = 0, so DU = 0; therefore, DU = Q – W = 0, or Q
= W |
|
d. |
DV = 0, so PDV = 0 and W = 0; therefore, DU = Q |
7. A thermodynamic process occurs, and the
entropy of a system decreases. What can be concluded about the entropy change
of the environment?
|
a. |
It decreases. |
|
b. |
It increases. |
|
c. |
It stays the same. |
|
d. |
It could increase or decrease, depending on the process. |
8. How is conservation of internal energy
expressed for an isovolumetric system?
|
a. |
Q = W = 0, so DU = 0 and Ui =
Uf |
|
b. |
Q = 0, so DU = –W |
|
c. |
DT = 0, so DU = 0; therefore, DU = Q – W = 0, or Q
= W |
|
d. |
DV = 0, so PDV = 0 and W = 0; therefore, DU = Q |
9. Which equation describes a process that takes
place at constant volume so that no work is done on or by the system?
|
a. |
DU = Q - W |
c. |
DU = - W |
|
b. |
Q = W |
d. |
DU = Q |
10. A heat engine performs 2000.0 J of net work
while adding 5000.0 J of heat to the cold-temperature reservoir. What is the
efficiency of the engine?
|
a. |
71.4% |
c. |
40.0% |
|
b. |
60.0% |
d. |
28.6% |
11. Which of the following processes for an ideal
gas system has an unchanging internal energy and a heat intake that corresponds
to the value of the work done by the system?
|
a. |
isothermal process |
c. |
adiabatic process |
|
b. |
isobaric process |
d. |
isovolumetric process |
12. A 4 mol ideal gas system undergoes an adiabatic
process in which it expands and does 20 J of work on its environment. How much
energy is transferred to the system as heat?
|
a. |
–20 J |
c. |
5 J |
|
b. |
0 J |
d. |
20 J |
13. A 4 mol ideal gas system undergoes an adiabatic
process in which it expands and does 20 J of work on its environment. What is
its change in internal energy?
|
a. |
–20 J |
c. |
0 J |
|
b. |
–5 J |
d. |
20 J |
14. When all the entropy changes in a process are
taken into account,
|
a. |
DS = 0 |
|
b. |
S2 > S1 |
|
c. |
S2 < S1 |
|
d. |
S2 = S1 |
15. How is conservation of internal energy
expressed for an adiabatic system?
|
a. |
Q = W = 0, so DU = 0 and Ui =
Uf |
|
b. |
Q = 0, so DU = –W |
|
c. |
DT = 0, so DU = 0; therefore, DU = Q – W = 0, or Q
= W |
|
d. |
DV = 0, so PDV = 0 and W = 0; therefore, DU = Q |
16. The first law of thermodynamics is actually a
restatement of
|
a. |
Newton's first law. |
c. |
the law of conservation of momentum. |
|
b. |
the law of universal gravitation. |
d. |
the law of conservation of energy. |
17. Which law of thermodynamics tells is that
whenever work is done the net change in entropy is always positive?
|
a. |
The 0th law |
c. |
The 2nd law |
|
b. |
The 1st law |
d. |
The 3rd law |
18. In an adiabatic process
|
a. |
energy as heat is not exchanged. |
c. |
energy as heat is quickly exchanged. |
|
b. |
energy as heat is slowly exchanged. |
d. |
energy as heat is completely removed. |
19. In order for energy to be exchanged between two
systems
|
a. |
the process must be adiabatic. |
c. |
the systems must be in thermal
equilibrium. |
|
b. |
the process must be isothermal. |
d. |
the systems must not be in thermal
equilibrium. |
20. By definition a cyclic system
|
a. |
never returns to its initial
condition. |
c. |
always returns to its initial
condition but with a tiny bit of ' lost' energy. |
|
b. |
always returns to its initial
condition. |
d. |
always returns to its initial
condition but with a tiny bit of 'extra' energy. |
21. Whenever the internal energy of a system
cahnges you know that
|
a. |
work was done on or by the system. |
c. |
the volume of the system also cahnged. |
|
b. |
the system is isolated. |
d. |
the temperature of the system also
changed. |
22. Every engine, including the human body, is a
heat engine. Every heat engine has a hot place and a cold place between which
work is done. This means that every heat engine
|
a. |
works best when the hot and cold place
are closest in temperature. |
c. |
works best when there is no difference
in the temperature between the hot and cold place. |
|
b. |
works best when the hot and cold place
are fartherest apart in temperature. |
d. |
works best when there is no hot or
cold place. |
23. Blowing up a balloon is an
|
a. |
isothermal thermodynamic process. |
c. |
isobaric thermodynamic process. |
|
b. |
isovolumetric thermodynamic process. |
d. |
adiabatic thermodynamic process. |
24. If a system has a high potential for change its
entropy must be
|
a. |
high. |
c. |
nonexistent. |
|
b. |
low |
d. |
unchangable |
25. When water condenses its entropy
|
a. |
decreases. |
c. |
remains unchanged. |
|
b. |
increases. |
d. |
falls to aero. |
Short Answer (90)
Answer the questions below in complete
sentences on your own paper. Answer each
question on its own page. Answer all questions in a vertically aligned 'a',
'b', 'c' format. You will receive ten points for each part of each question.
26. Consider a salt solution set in the sun.
a) State the second law of thermodynamics in terms of entropy.
Answer the following questions:
b) Does the dissolved salt have more or less entropy than salt
crystals? What happens to the entropy of the salt as the water evaporates?
c) Does the liquid water have more or less entropy than the
evaporated water? What happens to the entropy of the water as it evaporates?
d) As the water evaporates the salt crystallizes; explain how this
does not violate the second law of thermodynamics, as stated above.
27. Consider the first two laws of thermodynamics.
a) State the first law of thermodynamics in terms of energy
conservation
b) Write the equation for the first law in symbols and in english
c) State the second law of thermodynamics in terms of energy
transformations
d) Explain why the first and second law do not contradict each
other.
e) Rewrite the first law equation so that it takes into
consideration your explaination.
PAPP Chapter 11:
Thermodynamics
Answer Section
MULTIPLE CHOICE
1. A
2. B
3. D
4. A
5. B
6. C
7. B
8. D
9. D
10. D
11. A
12. B
13. A
14. B
15. B
16. D
17. C
18. A
19. D
20. B
21. A
22. B
23. D
24. B
25. A
SHORT ANSWER
26. Considering a salt solution set in the sun.
a) The second law of thermodynamics in terms of entropy states
that for all natural preocesses entropy always increases. According to the
second law of thermodynamics, stated in this way:
b) Dissolved salt has more entropy than crystallized salt. So, as
the salt crystallizes the entropy of the salt decreases.
c) Liquid water has less entropy than water vapor. So, as the
water vaporizes the entropy of the water increases.
d) As the water vaporizes the salt crystallizes. This process does
not violate the second law of thermodynamics as stated above because the change
in entropy of the salt is less than the change in entropy of the water. In
other words, the vaporized water has more entropy than the dissolved salt.
Therefore the net change in entropy for the vaproizing water-crystalizing salt
process is positive.
27. a) The first law of thermodynamics in terms of
consrvation of energy states that energy is always conserved, or energy cannot
be created nor destroyed.
b) The equation for the first law is DU = Q - W. The change
in the internal energy of a system is equal to the sum of the energy as heat
that enters or leaves the system and the work done on or by the system.
c)The second law of thermodynamics in terms of energy
transformation states that whenever energy is transferred from one kind to
another or from one place to another some energy is always lost, or 'gets
away’.
d) The first law contradicts the second law only if you do not
take into consideration the energy that "got away". Without this energy that 'got away' it seems
that you are always left with less energy than you started with. This is, of course, a violation of the first
law.
The first law is not contradicted by the second law if you take
into account all of the energy that was transferred from one kind to another or
from one place to another along with the energy that "got away". By doing this all of the energy you stated
with would equal all the energy you ended up with.
e) One might re-write the first law equation to reflect this: DU = (Q - W) + Q